There is a structure called employee that holds information like employee code, name, date of joining. Write a program to create an array of the structure and enter some data into it. Then ask the user to enter the current date. Display the names of those employees whose tenure is 3 or more than 3 years according to the given current date.

#include<stdio.h>
#include<conio.h>

void printinfo(struct employee k);

struct employee
{
	int code;
	char name[30];
	int doj[3];
}hcl[50] = {

	001, "Shahnawaz", 13, 1,2006,
	004, "Amit Puri", 21, 6,2008,
	102, "Irfan Moin", 12, 5, 2012,
	131, "Shabnam", 16, 1, 2014
};

int main()
{
	int i, d[3];
	printf("\nEnter the current date (dd mm yyyy) : ");
	scanf("%d%d%d", &d[0], &d[1], &d[2]);
	printf("\nEmployees with greater than or equal to 3 years of tenure\n\n");
	for (i = 0; i < 4; i++)
	{
		if (d[2] - hcl[i].doj[2] > 3)
			printinfo(hcl[i]);
		else if (d[2] - hcl[i].doj[2] == 3)
		{
			if (d[1] - hcl[i].doj[1] > 0)
				printinfo(hcl[i]);
			else if (hcl[i].doj[1] == d[1])
			{
				if (d[0] - hcl[i].doj[0] >= 0)
					printinfo(hcl[i]);

			}
		}
	}
	_getch();
	return 0;
}

void printinfo(struct employee e)
{
	printf("\nCode : %d", e.code);
	printf("\nName : %s", e.name);
	printf("\nDate of joining : %d-%d-%d\n", e.doj[0], e.doj[1], e.doj[2]);
}