# Write a program that takes a set of names of individuals and abbreviates the first, middle and other names except the last name by their first letter.

F
Sections
9
Exercises
``````#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<Windows.h>
#include<malloc.h>

#define Space 32/*ASCII v*/

char* last_name(char *line)/*It will return char pointer*/
{
char temp[20], *p;
int i, j, l = 0;
for (i = j = 0; line[i] != '\0'; i++)
{
if (line[i] == Space)/*If Sace if encounter so the first letter of the word will saved in the temp*/
{
temp[l] = line[j];
l++;
temp[l] = Space;/*after first leter we are giving a space*/
l++;
j = i + 1;
}
}
if (line[i] == '\0')
{
for (; line[j] != '\0'; j++, l++)
temp[l] = line[j];
temp[l] = line[j];
}
/*As if a pointer string cannot be assigned to a simple char variable so, a pointer
of char is made and then assign peration if performed*/
p = (char*)malloc(sizeof(strlen(temp) + 1));/*p getting size*/
return p;/*assigning p to the name[i] in man function as this function returns char pointer*/
}

int main()
{
char *name[10];
int i = 0, j;
char ans = 'y', *p, naam[30];
while (ans == 'y')
{
puts("\nEnter the full name : ");
gets_s(naam);
p = (char*)malloc(sizeof(strlen(naam) + 1));
strcpy(p, naam);
name[i] = p;
name[i] = last_name(name[i]);
printf("\nWant to enter another name (y/n) : ");
scanf("%c", &ans);
i++;
while (getchar() != '\n');/*So that we can get the next name, otherwise \n will be saved in the buffer. (fflush(stdin) don't woirk)*/
if (i > 9)/*Names cannot be more than 10*/
break;
}
if (i >= 10)/*If trying to enter names more than 10*/
puts("\nNo more names can be entered");
system("cls");
puts("\n\t\tName in the given format.");
for (j = 0; j < i; j++)
puts(name[j]);
_getch();
return 0;
}``````