Write a program to count the number of occurrences of any two vowels in succession in a line of text. For example, in the sentence "Pleases read this application and give me gratuity" such occurrences are ea, ea, ui.

#include<stdio.h>
#include<conio.h>

#define VowelisOccur str[i] == 'a' || str[i] == 'A' || str[i] == 'e' || str[i] == 'E' \
	|| str[i] == 'i' || str[i] == 'I' || str[i] == 'o' || str[i] == 'O' || str[i] == 'u' \
	|| str[i] == 'U'

int find_vows(char * str)
{
	int i, count = 0;
	printf("\nVowels in successions : ");
	for (i = 0; str[i] != '\0'; i++)
	{
		if (VowelisOccur)/*If first vowel is occur*/
		{
			i++;/*To check next vowel*/
			if (VowelisOccur)/*If second vowel after first if occur*/
			{
				printf("%c%c ", str[i - 1], str[i]);/*Printing two simultaneous vowels*/
				count++;/*Counting Two simultaneous vowels*/
			}
		}
	}
	return count;
}
int main()
{
	char str[100], tot_vow;
	printf("Enter the string : ");
	gets_s(str);
	tot_vow = find_vows(str);
	printf("\n\nTotal number of vowels in successions are : %d\n", tot_vow);
	_getch();
	return 0;
}